I'm doing a science fair project on what battery has the most amount of power. My experiment is to leave a battery powered appliance on until the battery runs out of energy. Then, the time will be recorded and compared. I want to spend the least amount of time possible with the experiment, using an appliance that uses a ton of power.
Any suggestions? Best Answer goes to first good answer.
Thanks!|||An electric automobile.
Other than that, the only ones are small ones, and of those, a laptop PC, which uses 30-50 watts, is probably the most.
The problem with most battery operated things, is that the power usage changes depending on what you do with them. A laptop, for example, uses more power during a disk access, for example, and when not used for a few minutes, goes to sleep, which cuts power down a lot.
My camera, if not used for a minute, shuts itself off.
But I don't see how you can gain any info from these. The battery life is determined by design, you can't change batteries to a dfiferent type.
.|||A UPS ( Un interrupted power supply).. when power fails , then UPS lights your whole hose using a 12 Volts 200A battery.. and it barely lasts for about 1.5 hours.|||a bored chicks vibrator|||How about my crap iPod? Barely lasts an hour.|||A simple flashlight which uses an incandescent light bulb is a big drain an it is commonly available in most homes. Next would be a battery operated motor such as a hand held portable fan.
But lets not forget Ohms law (E= I * R) and how you can use a simple resistor to drain the battery at a known and consistent rate (compared to a radio that varies in volume from song to song for example).
You can buy a couple of 10 Watt resistors at radio shack
http://www.radioshack.com/search/index.j鈥?/a>
http://www.radioshack.com/product/index.鈥?/a>
You can use two 10Ohm 10Watt resistors wired in parallel for 5 ohms, wired in series for 20 ohms or individually for 10 ohms and connect these to a single 1.5V cell to drain it.
Power is voltage * current (P= I * E) or current squared time resistance.
1.5V / 5 = 0.3 A or 300mA
0.3 * 0.3 * 5 = 0.45 Watts This is well below the 10W rating and will easily handle the power dissipation .
EDIT
Using a resistor on a single cell will also simplify your testing and lower your testing costs because you will only need to drain one battery (cell) at a time. Plus you can buy a battery holders for different sized batteries which will hold one cell.
http://www.radioshack.com/search/index.j鈥?/a>
EDIT
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Have you considered using a data logger to let a computer monitor and record voltage readings for you? You can get a cheap one for $29 and if you use it in a science fair it can be FREE.
See these links for detail on how to get a free Data Logger
Application Form:
http://www.dataq.com/science-fair/scienc鈥?/a>
Data Logger:
http://www.dataq.com/products/startkit/d鈥?/a>
Source(s):
http://www.dataq.com/science-fair/scienc鈥?/a>
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